![cow pig chicken math problem cow pig chicken math problem](http://3.bp.blogspot.com/-b0RJKypG0Ok/UFzVawG__OI/AAAAAAAAEGk/duBxmBV0IfY/s400/farm.jpg)
work out a solution that satisfies one condition but not the other.in some cases, give up before really trying anything because the answer won’t be obvious or workable using a “standard” pathway, or they are paralyzed by the fear of being wrong.probably divide the number of animals by 2, then not know what to do with the answer they get.try to add the animals and the feet together, not understanding that their sum will represent neither.
![cow pig chicken math problem cow pig chicken math problem](https://ecdn.teacherspayteachers.com/thumbitem/A-Z-Alphabet-Animal-Craft-eBook-30-Printable-Templates-Included-3739005/original-3739005-1.jpg)
Multiply to calculate the total number of feet (guess and check) until you arrive at the correct totals. Select an arbitrary number of animals of each kind.Work backwards from 56 and 22, by adding and subtracting as needed.Mark off 4 marks for each goat and 2 for each chicken. Create a system using columns of 4’s and 2’s.Start with a guess and check, then add or subtract animals and corresponding feet until you arrive at numbers that satisfy both conditions of the problem. Draw pictures representing 4-footed goats and 2-footed chickens.There are lots of other ways that students could solve this problem. I complete my table, systematically decreasing the number of feet by decreasing goats and adding chickens, while maintaining the necessary number of animals. If I’m using this method to show a possible solution pathway, this would be the point at which I ask the students if they see a pattern developing. I begin by deducting one goat, adding one chicken, and reconciling the number of feet row by row. I can then work backwards to my solution. Once my columns are in place I can see that I have 10 feet too many. Using this info, I could create a six-column table. I might divide 22 by 2 and use 11 + 11 as a jumping-off point. Start with a guesstimated number for the two animals. Finally, I checked my values by substituting both into the second equation. I found that there must be 6 goats and 16 chickens. Once I had the value for g, I used it to solve for c in the first equation. Then I substituted my new value for c into the second equation. To solve this problem, I used an algebraic system of two equations, letting c represent the number of chickens and g represent the number of goats.įirst, I solved for one variable in terms of the other in the first equation. It is non-discriminatory in that I can, have, and did give this and a similar problem to students learning at the most basic level and those taking the HSE exam in the same week.
![cow pig chicken math problem cow pig chicken math problem](https://www.clker.com/cliparts/6/1/9/9/11949837281658100694tante_orme_sulla_neve_ar_01.svg.med.png)
This problem pushes students to think outside the box.
![cow pig chicken math problem cow pig chicken math problem](https://image2.slideserve.com/4009767/the-rooster-who-lost-his-crow-l.jpg)
COW PIG CHICKEN MATH PROBLEM SERIES
Here is the first in a series of riddles of the week. Here at Popular Mechanics, we love riddles, brain-teasers, and logic puzzles so much that we decided to post one a week.